Question

Construct A PQR in which PQ=4.5 cm, QR = 5 cm and RP=6 cm​

Answer 1

$\huge \mathfrak \green{Question↓}$

Construct ∆PQR in which

PQ=4.5 cm, QR = 5 cm

and RP=6 cm

$\huge \mathfrak \green{Answer↓}$

Steps of Construction :

→ First draw a rough sketch of given measures.

→ Draw a line segment of PQ= 4cm.

→With Q as center and radius 5cm draw an arc. ( Open your compass 5cm )

→With P as center and radius 6cm draw ⠀another arc cutting the first arc at point R. ( Open Your compass 6cm )

→Join PR and RQ.

Hence, ∆PQR is required

Triangle

(Step by step construction is given in pic above)

Hope It Helps You!!....

Answer 2

Answer:

Steps of Construction :

→ First draw a rough sketch of given measures.

→ Draw a line segment of PQ= 4cm.

→With Q as center and radius 5cm draw an arc. ( Open your compass 5cm )

→With P as center and radius 6cm draw ⠀another arc cutting the first arc at point R. ( Open Your compass 6cm )

→Join PR and RQ.

Hence, ∆PQR is required

Step-by-step explanation:

hope it helps you