Question

Construct a ∆ PQR, in which PQ = 4.8 cm, QR = 5 cm, and PR = 5.6 measure Q​

Answer 1

Answer:

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Step-by-step explanation:

As per the given data points M and N are the midpoints of △PQR

∴ MQ=

2

1

PQ=2.8cm

Similarly, NR=

2

1

PR=2.4cm

MN=

2

1

QR=

2

1

×6.2=3.1cm

∴ Perimeter of trapezium = MQ+QR+NR+MN=2.8+6.2+2.4+3.1=14.5cm

Answer 2

Step-by-step explanation:

(1) Draw a line PQ = 6 cm.

(2) Using compass taking P as centre draw an angle ∠P = 60°.

(3) Using compass taking Q as a centre draw an angle ∠Q = 30°.

(4) PS and QT intersect each other R.

(5) ∆ RPQ is the required triangle.

On measuring; ∠R = 90°, length of PR = 3 cm.

Hope this will help you

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