Question

Construct a ∆PQR in which PQ = 6cm , PR=7cm , P=140°

Answer 1

construction :

1. Draw a st. line of 7 cm and name it as P and R.

2. Measure an angle of 140° using a protractor as from P and draw a long st. line from it and name it's end as x.

3. Mark 6 cm from P in the st. line PX and draw an arc of 6 cm and name that point as Q

4. join it with the point R to form a triangle.

5. Now a triangle PQR is ready.