Question

Construct A PQR, in which QR = 4.2 cm, m<Q = 40° and PQ + PR = 8.5 cm

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Answer 1

Step-by-step explanation:

$\huge \tt{\text{A} \blue{N} \orange{S} \pink{W} \green{E} \red{R}} :) :)$

Steps of constructions:-

1. Draw seg QR of length 4.2 cm.
2. Draw ray QT such that ∠RQT = 40°.
3. Mark point S on ray QT such that QS = 8.5 cm.
4. Draw seg RS.
5. Construct the perpendicular bisector of seg RS.
6. Draw perpendicular bisector of SR which intersects ray QT. Mark the point as P.
7. Draw seg PR.

Hope it helpful...☃️