Question

Construct a PQR in which QR 5.4 cm, Q = 60° and PQ-PR=3.5 cm.

Answer 1

Here are the following steps which will help you to construct a triangle PQR, where OR = 5.4 cm, ∠Q = 60° and PQ - PR = 3.5 cm.

Step 1 : Draw a line segment QR of length 5.4 cm.

Step 2 : At point Q, draw an angle of 60° say ∠YQR and extend the line QR to Z in the opposite side.

Step 3 : Now, take length of 3.4 cm in your compass and cut a line segment on QZ. Label as S.

Step 4 : Join SR.

Step 5 : Now, draw a perpendicular bisector AB of line segment SR. It will intersect QY at a point P.

Step 6 : Join PQ as well as PR.

Step 7 : Mark the measurements carefully.

Now, we have gotta our required triangle PQR.