Question

Construct a ∆ PQR, in which QR = 5 cm, ∠ R = 90 degree and PQ = 5.8 cm.

Answer 1

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$\large \green{Answer}$

➊ Draw a line segment QR of length 5cm.

➋ Now, we draw 90° degrees from point R.

➌ Taking R as centre, 5.8 cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

➍ Joint PR and label the sides Thus, PQR is the required triangle .

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Answer 2

Answer:➊ Draw a line segment QR of length 5cm.

➋ Now, we draw 90° degrees from point R.

➌ Taking R as centre, 5.8 cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

➍ Joint PR and label the sides Thus, PQR is the required triangle .

Step-by-step explanation: