Math, asked by morngrashi5467, 3 months ago

Construct a ∆ PQR, in which QR = 5 cm, ∠ R = 90 degree and PQ = 5.8 cm.

Answers

Answered by Anonymous

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$\large \green{Answer}$

➊ Draw a line segment QR of length 5cm.

➋ Now, we draw 90° degrees from point R.

➌ Taking R as centre, 5.8 cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

➍ Joint PR and label the sides Thus, PQR is the required triangle .

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Answered by dxb3617514

Answer:➊ Draw a line segment QR of length 5cm.

➋ Now, we draw 90° degrees from point R.

➌ Taking R as centre, 5.8 cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

➍ Joint PR and label the sides Thus, PQR is the required triangle .

Step-by-step explanation:

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