Question

construct a ∆PQR in which QR = 6cm, angle q=60° and PR-PQ = 3cm.​

Answer 1

Step-by-step explanation:

Draw a line PQ=3CM .

NOW MAKE AN ARCH FROM P AND MAKE 60° .

THEN TAKE 6CM MEASURE IN COMPASS AND CUT AN ARCH AND MARK IT 'R' JOIN RQ.

The required triangle is formed by SAS triangle construction

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