Construct a ∆ PQR in which QR =7 cm. <Q = 75° and PQ+PR = 3 cm
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In a triangle PQR, the sum of the any two sides of the triangle will be always greater than the length of the third side.
for example if we keep Q = 0° (which is not possible) it has to be a straight line equal to QR (7cm) to touch R. Even if Q is 1 ° PQ+PR > 7cm to form a triangle.
for example if we keep Q = 0° (which is not possible) it has to be a straight line equal to QR (7cm) to touch R. Even if Q is 1 ° PQ+PR > 7cm to form a triangle.
rishilaugh:
so you mean to say it will not be possible to construct such triangle ?
Yes, it is not possible
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