Question

Construct a ∆PQR in which QR= 7cm, <Q=60 °

and PR-PQ =3cm.
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Answer 1

Hope it helps

STEP OF CONSTRUCTION:

1. Draw QR = 7cm.
2. Construct angle PQR = 60°.
3. Produce XQ downwards to a point X'.
4. Set off PM = 3cm along QX'.
5. Join MR.
6. Draw the perpendicular bisector of MR, meeting QX at P.
7. Join PR

then, ∆ PQR is the required triangle.