Question

construct a ∆PQR ,where Q=90°,PR =5cm,QR=4cm​

Answer 1

Answer:

here is your answer

^–= PQR

Q= 90° PR=5 cm and QR =4 cm

1. first I have made a rough triangle in which QR =4 cm and PR =5 cm
2. then I make a 4 cm triangle which name is QR
3. then it is given A=90°
4. THEN I MADE A ARA then I easily got 90•
5. then we have to found PR
6. PR =5 cm then I measure in the scale by the help of compass.
7. then I put a mark in the 90° line
8. then I easily got my triangle