Question

construct a ΔPQR whose perimeter is 12cm and the length of whose sides are in the ratio 3:2:4.

please help me in this. i am not able to construct it.

Answer 1

☺Heya dear !

•to find the lengths of the sides of triangle , and constructed triangle , please consult the attached image above...

•the steps of construction are as follows :-

>>firstly , as it the names of sides is not specified, take any length and draw a straight line , of its length. as for instance, I've taken BC as base with 3.9 cm as length and drawn a straight line.

>>next , take the next length as radius in your compass and draw an arc from B. as I've taken 2.6 cm for 2nd length.

>>then, take the last length in your compass as radius and from C , cut the previous arc .

>>this cut point is the vertice of triangle .

>>mark it A , and join AB and AC.

>>the required triangle is ABC.

_________________________

Hope it helps u dear ! ^_^

Answer 2

Solution :

Construct a line segment AB=12 cm

Construct a ray AX which makes an acute angle with the line segment AB which is drawn in a downward direction

From the point A set off (3+2+4)=9 at equal distance along the line AX

The points L,M,N should be marked on AX where AL=3 units, MN=4 units and LM=2 units

Join the points NB

From L and M, construct LQ ∣ ∣ NB and MR ∣ ∣ NB which cuts AB at the points Q and R

Consider Q as centre and AQ as radius, construct an arc

Consider R as centre and RB as radius, construct another arc which cuts the previous arc at the point P

Join the points PQ and PR

Therefore, △PQR is the required triangle.

I HOPE MY ANSWER WILL HELP YOU.