Construct a ∆PQR whose perimeter is equal to 14 cm, ∠P = 45° and ∠Q = 60°. Give
justification
Answers
Answered by
2
Answer:
Answer=>75°
Step-by-step explanation:
We know that the sum of a triangle is 180°
∆R we take x
∆PQR=180°
45°+60°+x=180°
105°+x=180°
By transposing
x=180°-105°
x=75°
Answered by
0
Answer:
Answer:
Answer=>75°
Step-by-step explanation:
We know that the sum of a triangle is 180°
∆R we take x
∆PQR=180°
45°+60°+x=180°
105°+x=180°
By transposing
x=180°-105°
x=75°
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