Construct A PYQ such that, PY = 6.3 cm, YQ = 7.2 cm
YZ 6
PQ = 5.8 cm. If
then construct A XYZ similar to A PYO,
A ,
YQ
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Step-by-step explanation:
Steps of construction:
i. Draw ∆ PYQ of given measure. Draw ray YT making an acute angle with side YQ.
ii. Taking convenient distance on compass, mark 6 points Y1 , Y2 , Y3 , Y4 , Y5 and Y6 such that YY1 = Y1 Y2 = Y2 Y3 = Y3 Y4 = Y4 Y5 = Y5 Y6 .
iii. Join Y5 Q. Draw line parallel to Y6 Q through Y to intersects ray YQ at Z. iv. Draw a line parallel to side PQ through Z. Name the point of intersection of this line and ray YP as X. ∆XYZ is the required triangle similar to ∆PYQ.
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