Question

construct a quadilateral PRQS, PQ=4.5cm, QR=3cm,angle, P=120degrees, angleR=60 degree,Pr=5.6cm

Answer 1

Step-by-step explanation:

"1. Draw a line segment PQ = 4.5 cm

2. Take a compass and keeping Q as a centre construct an angle of 60 degrees.

3. Now take the radius of 3 cm, draw an

arc on the 60-degree angle line. The

intersection point of the 3 cm arc and 6

degrees will be R.

4. As per the supplementary property of a parallelogram, SPQ + PQR = 180 Hence draw an angle of 120 degrees on point P.

5. Now draw an arc of 3 cm and mark it as S

6. Join PQRS to form a parallelogram.