Question

construct a quadnilateral DEAR where DE=4CM , EA=5CM , AR= 4.5 CM , LE= 60° and and LA=90°​

Answer 1

Answer:

Steps of Construction

(i) Draw BC = 7 cm.

(ii) Construct ∠YBC = 75°.

(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm.

(iv) Join CD.

(v) Draw the perpendicular bisector of CD meeting BY at A.

(vi) Join AC to obtain the required triangle ABC.

Justification

Since A lies on the perpendicular bisector of CD.

∴ AC = AD

Now BD = 13 cm

⇒ BA + AD = 13 cm

⇒ BA + BC = 13cm

Hence, △ABC is the required triangle.

Step-by-step explanation:

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Answer 2

Answer:

Construct a ABC in which BC = 7 cm, and ∠B = 65˚

and ∠C = 75˚

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