Math, asked by ansh02math, 4 months ago

construct a quadrilater pqrs where Pq 4 CM. qr 6 cm RS 5 CM PS 5.5 CM pt 7 cm​

Answers

Answered by SUNNY90850
2

correct \: question

construct a quadrilater PQRS where PQ = 4 Cm, QR = 6 Cm RS 5 CM RS = 5.5 Cm and PR = 7Cm.

 \blue {\bold{solution}}

  1. Draw a diagonal PR of length 7 Cm.
  2. Taking 4 Cm as radius, and PS as center, draw an arc on top of PR.
  3. Taking 6 Cm as radius, and R as center, draw an arc on top of PR.
  4. Taking 5•5 Cm as radius, and P as center.
  5. Taking 5 Cm as radius, and R as center, draw an arc below of PR.
  6. Let Q be the point where arcs intersect on top of PR and S be the point where arcs intersect below PR. Join PQ, PR, PR, SR.

Label the sides.

Result:- PQRS is the required quadrilateral.

Description By TuTor:- Please draw the chart also in shown image [ Draw before write these all. ]

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