Math, asked by kanishakrathore65432, 2 months ago

Construct a quadrilateral ABCD, given that
* AB - 3.5 cm, BC-5 cm, CD -4.5 cm
AC -5 cm and BD =6 cm.​

Answers

Answered by mt1192
0

Answer:

Draw a line segment AB=3.5cm

Draw a line segment AB=3.5cm⇒  Take B as center with radius 4.5cm and draw an arc.

Draw a line segment AB=3.5cm⇒  Take B as center with radius 4.5cm and draw an arc.⇒  Take A as center with radius 6.6cm and draw an arc, which is meeting previous arc at point C.

Draw a line segment AB=3.5cm⇒  Take B as center with radius 4.5cm and draw an arc.⇒  Take A as center with radius 6.6cm and draw an arc, which is meeting previous arc at point C.⇒  Take C as center with radius 3.5cm and draw an arc.

Draw a line segment AB=3.5cm⇒  Take B as center with radius 4.5cm and draw an arc.⇒  Take A as center with radius 6.6cm and draw an arc, which is meeting previous arc at point C.⇒  Take C as center with radius 3.5cm and draw an arc.⇒  Take A as center with radius 5.6cm and draw an arc, which is meeting previous arc at point D.

Draw a line segment AB=3.5cm⇒  Take B as center with radius 4.5cm and draw an arc.⇒  Take A as center with radius 6.6cm and draw an arc, which is meeting previous arc at point C.⇒  Take C as center with radius 3.5cm and draw an arc.⇒  Take A as center with radius 5.6cm and draw an arc, which is meeting previous arc at point D.⇒  Join BC,AC,CD and AD

Draw a line segment AB=3.5cm⇒  Take B as center with radius 4.5cm and draw an arc.⇒  Take A as center with radius 6.6cm and draw an arc, which is meeting previous arc at point C.⇒  Take C as center with radius 3.5cm and draw an arc.⇒  Take A as center with radius 5.6cm and draw an arc, which is meeting previous arc at point D.⇒  Join BC,AC,CD and AD∴  ABCD is a required quadrilateral.

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