Question

construct a quadrilateral ABCD, given that AB=5cm, BC=6cm, triangle B=60degree, triangle C=120degree and CD=5cm.

fast...... ​

Answer 1

Answer:

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Answer 2

Given : A quadrilateral A B CD, in which, AB=5  cm, BC = 6 cm, CD =6.5 cm , angle B= 105° and angle C = 75°

Steps of construction

(1) Draw a line segment B C of length 6 cm.

(2) At Point B and C , with the help of Compass draw angle of  105° and 75° respectively.Name the rays as C M and B Z respectively.

105°→Draw an angle of 120° and 90° and draw angle bisector between 90° and 120°.

75°→Draw angle bisector of 60° and 90°.

(3) From C , mark an arc at a distance of 6.5 cm on ray CM.You will get point D.

(4) From B , mark an arc at a distance of 5 cm on ray B Z.You will get point A.

(5) Join A and D.

This is required trpzoid A B CD.

here, AB ║CD→→∠B+∠C=180°[If sum of interior angles on the same side of transversal is supplementary then lines are parallel.]