Question

Construct a quadrilateral ABCD given that BC =6 CM CD=4CM ANGLE B=45 DEGREE ANGLE C=90 DEGREE ANGLE D=120 DEGREE

Answer 1

I hope it will help you

Answer 2

So $ABCD$ is the required triangle.

Step-by-step explanation:

Given;

Construct a quadrilateral $ABCD$ where $BC=6cm$,$CD=4cm$,$\angle B=45degree$,$\angle C=90degree$ and $\angle D=120degree$

Following steps:

• Draw a line $BC=6cm$
• At point $C$, draw an angle $90$ degree and extend it like $CE$
• From point $C$,cuts a measurement  $4cm$ on line $CE$ which is known as $D$
• At point $D$,draw an angle $120degree$ and extend it like $DF$
• At point $B$, draw an angle $45degree$ and its extend portion cuts the line $DF$ at point $A$

Now $ABCD$ is the required triangle.