Question

construct a quadrilateral abcd in which ab = 2.7 cm , bc = 3.5 cm, cd = 4 cm, ad =6cm and <b =90°​

Answer 1

Step-by-step explanation:

First draw line bc of 3.5 cm, then construct an angle of 90 degree at point B.cut an arc of 2.7 cm on the arrow and name the point as A.the keeping the pointer of the rounder on point A cut an arc at a distance of 6 cm.now keeping the pointer of te rounder on point C at a distance of 4 cm cut the earlier arc, name the intersecting point as D.There it is, the quadrilateral ABCD is constructed.

hope it's helpful to you dear

Answer 2

Answer:

Analysis→

Here we're given some measurements of sides:- AB= 2.7 cm, BC= 3.5 cm, CD= 4 cm, AD= 6 cm, and ∠B= 90°. So let consider BC as the base as ∠B is a right angle.

Given→

• AB= 2.7 cm.
• BC= 3.5 cm.
• CD= 4 cm.
• AD= 6 cm.
• ∠B= 90°

To Perform→

Construction of the quadrilateral with given measurements.

Answer→

• For diagram, refer to the pic provided.

Steps Of Construction:-

1. Draw a base BC= 3.5 cm using a ruler.
2. For B, construct a 90° angle using a compass. ( You can also use a Protractor).
3. Now extend a line through B at 90° and make a arc 2.7 cm on it using the compass. And name it A.
4. From A, extend your compass 6 cm and make an arc.
5. Now from C, make and arc 4 cm away that intersects the arc made of 6cm. Now name the point of intersection as D.
6. Join the line AD, and CD. Now the construction is complete. $\Large\checkmark$

HOPE IT HELPS.