Construct a quadrilateral abcd in which ab=3.5cm bc=3.8cm cd=4.5cm da =5cm bd = 5.6cm
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Procedure to draw a quadrilateral
1. Draw a line segment of ab = 3.5 cm
2. Measure angle 60° from point 'a' by using protractor.
3. According to property of Quadrilateral
∠a + ∠b + ∠c + ∠d = 360°
60° + ∠b + 120° + 75° = 360°
∠b = 105°
4. Measure ∠105° AT point b and draw a line.
5. measure length = 6.5 cm with the help of compass and cut the arc at the line from point 'b'. you will get point 'c'
6. at point 'c' measure ∠120° and draw a line, which cuts the line drawn from point 'a'.
7. measure the angle 'd', you will find that it measures 75°
For the diagram please find the file attached.
1. Draw a line segment of ab = 3.5 cm
2. Measure angle 60° from point 'a' by using protractor.
3. According to property of Quadrilateral
∠a + ∠b + ∠c + ∠d = 360°
60° + ∠b + 120° + 75° = 360°
∠b = 105°
4. Measure ∠105° AT point b and draw a line.
5. measure length = 6.5 cm with the help of compass and cut the arc at the line from point 'b'. you will get point 'c'
6. at point 'c' measure ∠120° and draw a line, which cuts the line drawn from point 'a'.
7. measure the angle 'd', you will find that it measures 75°
For the diagram please find the file attached.
Attachments:
Answered by
6
first construct a triangle with bc as base .
now, from b cut an arc of 5.6cm
and cut another arc of 4.5cm from c
you'll get a triangle bdc
now, with be as base
from b cut an arc of length 3.5cm
from d, cut an arc if 5cm
now, from b cut an arc of 5.6cm
and cut another arc of 4.5cm from c
you'll get a triangle bdc
now, with be as base
from b cut an arc of length 3.5cm
from d, cut an arc if 5cm
Attachments:
Jey2003:
this is based only on constructions
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