construct a quadrilateral ABCD in which AB=3.5cm ,BC=4 cm ,CD=4.5cm ,DA=5 cm and BD=5.5cm. measure AC
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Given :-
AB = 3.5 cm.
BC = 4 cm.
CD = 4.5 cm.
DA = 5 cm.
BD = 5.5 cm.
AC = ?
Solution :-
Step of constructions :-
● Draw a line AB = 3.5 cm with radius = 5 cm & centre A draw an arc.
● With radius 5.5 cm & centre B, draw an arc cutting the previous arc.
● Name the intersection as point D.
● With radius = 4 cm, and centre B, draw an arc.
● With radius = 4.5 cm & centre draw an arc cutting previous arc.
● Name the intersection point = C.
● Join OB, AC, CD, OA.
Done
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