construct a quadrilateral ABCD in which AB=3cm,Bc=4cm,CD=5.5cm,DA=6m,BD=9cm
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I have attached the answer to the question you have asked:
Steps of construction:
- Draw a line segment BD = 9 cm.
- Taking B as centre, draw an arc of 3 cm.
- Taking D as the centre, draw another arc of 6 cm which intersects the first arc.
- Mark the point of intersection - 'A'.
- Taking B as the centre again , draw an arc downwards of 4 cm.
- Taking D as the centre , draw an arc of 5.5 cm which intersects the arc which is = to 4 cm.
- Mark the point of intersection - ' C'.
- Therefore, you have completed the construction using these steps.
Hope this answer helps you...If it does then mark me as the brainliest
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idont no because i am also searching bro
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