Construct a quadrilateral ABCD in which AB = 4.4cm, BC = 4cm; CD= 6·4cm DA= 2.8cm and BD = 6.6Cm video explained pls or step by step
Answers
Answer:
Construct the following quadrilaterals:
(i) Quadrilateral ABCD
(ii) Quadrilateral JUMP
AB = 4.5 cm
JU = 3.5 cm
BC = 5.5 cm
UM = 4 cm
AD = 4 cm
MP = 5 cm
AD = 6 cm
PJ = 4.5 cm
AC = 7 cm
PU = 6.5
(iii) Parallelogram MORE
(iv) Rhombus BEST
OR = 6 cm
BE = 4.5 cm
RE = 4.5 cm
ET = 6 cm
EO = 7.5 cm
Sol. (i) First we draw a rough sketch of a quadrilateral ABCD and write down its dimensions as shown. We may divide it into two conveniently constructible Δs ABC and ACD.
The given details are AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, DA = 3.8 cm and BD = 6.6 cm. Divide the quadrilateral into two triangles i.e., ΔABD and ΔBCD Steps to construct a quadrilateral: Step 1- By using SSS congruency rule, Draw line BD of length 6.6 cm. Step 2- Cut an arc with B as the centre and radius BC = 4cm. Do the same by taking D as centre and radius CD = 6.4 cm. Step 3- Now join the intersection point from B and D and label it as C. Step 4- Now for vertex A, cut an arc by taking B as the center and radius BA = 4.4cm. Do the same by taking D as center and radius DA = 3.8cm. Step 5- Join the intersection point from B and D and label it as A.