Math, asked by mauryaanjali402, 7 hours ago

Construct a quadrilateral ABCD in which AB = 4.5 cm, BC = 3.5 cm, CD= 5 cm, angle B = 45° and angle C = 150°.​

Answers

Answered by ghoshronak407
0

Answer:

Take BC as Base of 3.5 cm and take B as centre make 45 degree and again same take C as centre and make 150 degree . Now again take B as centre and draw an arc of 4.5 and mark as A . Again now take C as centre and draw an arc of 5 cm now join all of the line .

Step-by-step explanation:

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Answered by GιяℓуSσυℓ
2

Answer:

⇒ Draw a line segment AB=4.5cm

⇒ Take B as center and draw an angle of 60°

⇒ Cut off BC=5.5cm

⇒ Take A as with radius 4.8cm and draw an arc.

⇒ Take C as with radius 5cm and draw an arc, which cuts off previous arc at point D

⇒ Join CD and AD.

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