construct a quadrilateral ABCD in which ab = 5.6 CM BC = 4 cm Angle A = 50° Angle B equal 105° and Angle B equal 80 degree
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∠A + ∠B + ∠C + ∠D = 360°
so 50° + 105° + ∠C + 80° = 360°
∠C = 125°
Now we will construct the quadrilateral ABCD
- First we will draw a line AB = 5.6 cm
- Now we will draw ∠BAX = 50° and ∠ABY = 105° (you can use protector for this)
- The radius we will take is 4cm and the center will be B for that you will draw and arc which will intersect the line BY at "C"
- Now we will draw an angle of 125° at "C" and the angle ray line AX at "D"
Attached is the quadrilateral.
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Hey mate here is your answer
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