Question

construct a quadrilateral ABCD in which ab = 5.6 CM BC = 4 cm Angle A = 50° Angle B equal 105° and Angle B equal 80 degree

Answer 1

∠A + ∠B + ∠C + ∠D = 360°

so 50° + 105° + ∠C + 80° = 360°

∠C = 125°

Now we will construct the quadrilateral  ABCD

- First we will draw a line AB = 5.6 cm

- Now we will draw ∠BAX = 50° and ∠ABY = 105° (you can use protector for this)

- The radius we will take is 4cm and the center will be B for that you will draw and arc which will intersect the line BY at "C"

- Now we will draw an angle of 125° at "C" and the angle ray line AX at "D"

Attached is the quadrilateral.

Answer 2

Answer:

Step-by-step explanation:

Hey mate here is your answer