Construct a quadrilateral ABCD in which AB = 5cm, BC =6.5cm, CD = 7cm, angle B=120° and angle C=90°
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Given Construct a quadrilateral ABCD in which AB = 5 cm, BC = 6.5 cm, CD = 7 cm, angle B = 120° and angle C = 90
- We need to construct a quadrilateral ABCD in which, AB = 5 cm, BC = 6.5 cm, CD = 7 cm, angle B = 120 degree and angle C = 90 degree.
- Draw a line segment BC of length 6.5 cm
- At the point B and C with the help of compass construct angle 120 degree and 90 degree.
- Let the lines be CP and BQ respectively.
- From C make an arc at a distance of 7 cm on the line CP. Mark the point as D.
- From B, make an arc at a distance of 5 cm on the line BQ. Mark the point as A.
- So Join A and D.
- Now ABCD is a quadrilateral.
- So AB is parallel to CD.
- Angle B + angle C = 180 degree
- The lines are parallel if the sum of interior angles on the same side of transversal is supplementary.
Reference link will be
https://brainly.in/question/7625456
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Answer:
angel B+angle C=180degrees
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