construct a quadrilateral ABCD in which ab = 6 CM = 5 centimetre angle A = 60 degree angle B = 100 degree and Angle d is equal 110 degree
Answers
Step-by-step explanation:
Given:
AB = 6.5 cm, AD = 5 cm, CD = 5 cm, ∠ BAC = 40o and ∠ ABC = 50o.
Steps for construction
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment AB = 6.5cm.
Step 3 : At A on AB make ∠BAX whose measure is 400 and at B on AB make ∠ABY whose measure is 500 . They meet at C.
Step 4 : With A and C as centres draw two arcs of radius 5cm and let them cut at D.
Step 5 : Join AD and CD . ABCD is the required quadrilateral.
Step 6 : From D draw DE⊥AC and from B draw BC⊥AC. Then measure the lengths of BC and DE. BC = h1 = 4.2 cm, DE = h2 = 4.3 cm and AC = d = 5 cm.
Calculation of area:
In the quadrilateral ABCD, d = 5 cm, h1 = 4.2 cm and h2 = 4.3 cm.
Area of the quadrilateral ABCD = 21d(h1+h2)
=21(57.8)(4.2+4.3)
=21×5×8.5
=21.25 cm2
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