construct a quadrilateral ABCD in which ab = 6 CM BC = 5 cm CD equal 4 cm equal 3 cm and diagonal AC equal to 3.5 CM
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Step-by-step explanation:
Make line AB (scale).
Use a rounder by point A for 3.5cm to make arc on B side of the line for C.
Use a rounder for 5cm to make arc by point B on B side of the line for C. The point where the arcs intersect is Point C. Assuming DA is 3cm (incomplete question), draw arc of 4cm by point C towards left side of C.
Draw arc of 3cm by A towards upper side of A. Point of intersection of both arcs should be Point D. U r Welcome
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Parmod Kumar dhikoli India
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