Math, asked by deepavipin05, 11 months ago

construct a quadrilateral ABCD in which AB=6cm AD=5cm angle A=60 degree angle B =100 angle D=110 degree​

Answers

Answered by Shailesh183816
6

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Given: AB = 6 cm, BC = 5cm, angle A = 55 degree, angle B = 110 degree and angle D = 90 degree.

Steps;

Angle sum property of a quadrilateral:

∠A + ∠B + ∠C + ∠D = 360 degree

55 + 110 + ∠C + 90 = 360 degree

∠C = 105 degree

1. Draw AB = 6 cm.

2. Take A as a centre construct an angle of 55 degrees and then from B make 110 degrees.

3. Take the measurement of BC = 5cm on the compass and cut the angle 110 line. Mark the point as C.

4. Now take C as a centre and construct 105 degrees.

5. The point where angle C and D will meet will be D.

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Answered by Anonymous
5

\huge\purple{Answer:-}

Given: AB = 6 cm, BC = 5cm, angle A = 55 degree, angle B = 110 degree and angle D = 90 degree.

Steps;

Angle sum property of a quadrilateral:

∠A + ∠B + ∠C + ∠D = 360 degree

55 + 110 + ∠C + 90 = 360 degree

∠C = 105 degree

1. Draw AB = 6 cm.

2. Take A as a centre construct an angle of 55 degrees and then from B make 110 degrees.

3. Take the measurement of BC = 5cm on the compass and cut the angle 110 line. Mark the point as C.

4. Now take C as a centre and construct 105 degrees.

5. The point where angle C and D will meet will be D.

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