Question

Construct a quadrilateral ABCD in which AB = 8.5cm, BC = 7.2cm, AD = 5cm, ∠B = 90° and ∠A = 30°.

Need steps of construction.
Thank you!
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Answer 1

Hi Atlas , This is your solution!

Solution :

See the figure also for better understanding.

Steps :

1] Draw a line segment BC = 7.2 cm

2] With B as centre , Mark a Ray at 90°

3] with B as centre and radius 8.5 cm , draw an arc at the Ray cutting at 'A' . The line segment produced is AB .

4] With A as centre , Mark a Ray at 30° .

5] With A as centre and 5 cm as diameter, cut an arc at the Ray. Mark It as D . The line segment formed is AD

6] Join C and D .

7] The quadrilateral ABCD is produced !

Answer 2

Given:-

Quadrilateral ABCD..

Solution:-

Refer to attachment..

$\textsf \red{Step \: of \: construction:}$

$\sf \pink{Step \: 1:}$ Draw line BC of 7.2 cm..

$\sf \pink{Step \: 2:}$Take a protector and measure 90° at the point B

$\sf \pink{Step \: 3:}$Now with point B draw a line of 8.5 cm and make a point A..

$\sf \pink{Step \: 4:}$Now with the point A measure 30° with protector and at the point A draw a line of 5 cm..

$\sf \pink{Step \: 5:}$Join line BA and AD and also join DC..

$\sf \pink{Step \: 6:}$Hence Quadrilateral ABCD is formed..