Question

construct a Quadrilateral ABCD in which AB=BC =3cm ,AD=CD=5 cm and angle d=120 degrees ​

Answer 1

First of all draw a straight line of 5 cm and mark its corners as C and D
Then make an angle of 120 degree from point D
Then take a rounder and make 5 cm and cut a arch of 5cm from point D
Mark the new point as A
Join A and D
Then from A cut an arch of 3cm
Cut an arch of 3cm from point C
The point of intersection mark as B
Then join C TO B AND ALSO A TO B

Answer 2

Draw AB = 4 cm.

At A, draw ∠PAB = 120°.

At B, draw ∠QBA = 60°.

From BQ, cut BC = 4.5 cm.

From C, draw an arc of radius 5 cm which meets AP at D.

Join CD.

Thus ABCD is the required quadrilateral