Question

construct a quadrilateral ABCD. in which AB=BC=AD=5cm,zAC=7cm and BD=6cm​

Answer 1

Step-by-step explanation:

⇒ With A as a center and radius AC = 8cm, draw an arc intersecting the previous arc at point C. ⇒ Again take B as a center and radius BD = 7cm, draw an arc. ⇒ With C as a center and radius CD = 7cm, draw an arc intersecting the previous arc at point D. ⇒ Join AC, BC, BD, CD and AD.

Answer 2

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Steps for construction :

• Draw a loine segment AB =5cm

• From A as centre, draw an arc above AB of radius 5cm.

• from point B as crentre draw an arc of 6 cm

ㅤㅤㅤwhich cuts the previous arc at D.

• from point A as centre draw an arc of radiu s 7cm.

• from point B as centre draw an arc of radiu

ㅤㅤㅤs 5 cm which cuts the previous arc ㅤㅤㅤat C

• Join AC , BD and CD.

• Thus ABCD is required quadrilateral

Look at the pic

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