Math, asked by manjunathmanju84, 1 month ago

Construct a quadrilateral ABCD in which AB equal to 3cm angle b equal to 120 degree ad equal to 5cm and one of its diagonal is 8 cm

Answers

Answered by piyushsahu624
2

Answer:

The given details are AB = BC = 3 cm, AD = CD = 5 cm and ∠B = 120°.

Steps to construct a quadrilateral:

Step 1- Draw a line AB = 3cm

Step 2- Construct and angle of 120o at B.

Step 3- Cut an arc of radius 3cm with B as the center to mark that point as C. Step 4- Cut an arc of radius 5cm with C as the center to mark that point as D. Step 5- Cut an arc of radius 5cm with A as the center to intersect at point D. Step 6- Now join BC, CD and DA

Step-by-step explanation:

https://www.sarthaks.com/?qa=blob&qa_blobid=4659960918104635197

diagram image is here

Answered by lifeofshaikh2000
0

Answer:

The given details are AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ∠B = 80°. Step 2- Construct and angle of 80o at B. Step 3- Cut an arc of radius 3.4cm with B as the center to mark that point as C. Step 4- Cut an arc of radius 5cm with A as the center to mark that point as D.

Step-by-step explanation:

Step I:- Draw the AB=3 cm

Step II:- Construct ∠ABC=1200.

Step III:- With B as the center and radius 3 cm, cut off BC=3 cm.

Step IV:- With C as the center and radius 5 cm and draw an arc.

Step V:- With A as the center and radius 5 cm and draw an arc to intersect the arc drawn in step IV at D.

Step VI:- Join AD,BC and CD.

Then, the obtained the required quadrilateral ABCD.

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