Question

construct a quadrilateral ABCD in which AB is equal to BC is equal to CD is equal to DA is equal to 5 cm and angle is equal to 120 degree what type of quadrilateral is it​

Answer 1

Construction:--

(i)Draw a line AB = 5 cm.

(ii) draw an angle of 120° at angleA and cut an arc of 5cm from A. Join AD.

(iii)cut an arc of 5cm from D and again from B, where the both arc cuts, join BC and CD.

hence quadrilateral ABCD is formed where AB = BC = CD = DA = 5cm and angle A = 120°.

hope it helps you

Answer 2

Step-by-step explanation:

steps of construction

1. Draw a line segment AB =5cm.

2. Draw <XAB = 120°.

3. Take an arc of 5 cm and cut AX from A at D.

4. Take two arcs of 5cm and 5cm and cut these arc from DB respectively . Let these arcs met at C.

5. Join B-C, D-C.

6. Hence , ABCD is the required quadrilateral.