Question

Construct a quadrilateral ABCD in which BC =4.5 cm,AB =4 cm, angleB =75°, angleA=90°, angleC =120°

Answer 1

Answer:

sum of all interior angle in quadrilateral is 360

then

angle D is 360-75-90-120

angle D is 360-285

=75

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Answer 2

Answer:

area = (1/2)(BC)(AB)

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√34

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√3434/√34 = √(25 + 4 - 4y + y^2)

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√3434/√34 = √(25 + 4 - 4y + y^2)square both sides

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√3434/√34 = √(25 + 4 - 4y + y^2)square both sides34 = 29 - 4y + y^2

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√3434/√34 = √(25 + 4 - 4y + y^2)square both sides34 = 29 - 4y + y^2y^2 - 4y - 5 = 0

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√3434/√34 = √(25 + 4 - 4y + y^2)square both sides34 = 29 - 4y + y^2y^2 - 4y - 5 = 0(y-5)(y+1) = 0

area = (1/2)(BC)(AB)17 = (1/2)(√(5^2 + (2-y)^2 ) (√3434/√34 = √(25 + 4 - 4y + y^2)square both sides34 = 29 - 4y + y^2y^2 - 4y - 5 = 0(y-5)(y+1) = 0y = 5 or y = -1

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