Construct a quadrilateral ABCD in which BC= 4.8 cm, CD = 4.8 cm, DA=3.2 cm, angle C = 60° and angle D =75°.(with diagram)
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Answer:
Steps :
- Draw AB = 4.3 cm.
- At B, draw ∠PBA = 75°
- Cut BC = 5.4 cm.
- From C & A, draw arcs of radii 5 cm and 4.8 cm respectively which intersect at D.
- Join AD and DC.
- ABCD is the required quadrilateral.
Steps :
- Draw BC = 5 cm.
- Draw ∠PCB = 60° and cut CD = 4.5 cm.
- From B and D, draw arcs of radii 6 cm and 5 cm respectively which intersect at A.
- Join AB and AD.
- Thus ABCD is the required quadrilateral.
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Answered by
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Step-by-step explanation:
first we draw DC=4.8cm
then we draw 75° in D point we take AD =3.2 cm
we draw 60°in c point we take BC = 4.8 cm then we joint AB
then we get ABCD nessary quadrilateral
..
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