Math, asked by mauryaanjali402, 1 month ago

Construct a quadrilateral ABCD in which BC= 4.8 cm, CD = 4.8 cm, DA=3.2 cm, angle C = 60° and angle D =75°.(with diagram)​

Answers

Answered by GιяℓуSσυℓ
1

Answer:

Steps :

  • Draw AB = 4.3 cm.
  • At B, draw ∠PBA = 75°
  • Cut BC = 5.4 cm.
  • From C & A, draw arcs of radii 5 cm and 4.8 cm respectively which intersect at D.
  • Join AD and DC.
  • ABCD is the required quadrilateral.

Steps :

  • Draw BC = 5 cm.
  • Draw ∠PCB = 60° and cut CD = 4.5 cm.
  • From B and D, draw arcs of radii 6 cm and 5 cm respectively which intersect at A.
  • Join AB and AD.
  • Thus ABCD is the required quadrilateral.

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Answered by anjanamanna12345
1

Step-by-step explanation:

first we draw DC=4.8cm

then we draw 75° in D point we take AD =3.2 cm

we draw 60°in c point we take BC = 4.8 cm then we joint AB

then we get ABCD nessary quadrilateral

..

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