Question

construct a quadrilateral ABCD, where AB = 5 cm,angle A=135°, angle B=60° ,angle C= 45°and BC=6.2 cm.​

Answer 1

Steps shown below.

Step-by-step explanation:

Given:

ABCD is a quadrilateral.

AB = 5 cm, ∠A = 135°, ∠B = 60°, ∠C = 45° and BC = 6.2 cm.

Steps of construction are as follows,

1. Draw AB = 5 cm

2. Taking A as a center, draw angle XAB = 135°

3. Taking B as a center, draw angle YBA = 60°

4. Taking B as a center and radius = 6.2 cm, draw an arc on BY. Name it as C.

5. Taking C as a center, draw angle ZCB = 45°. Let it cut XA at D.

Hence, ABCD is a required quadrilateral.  

Answer 2

Step-by-step explanation:

Step-1 Draw BC=6.2cm

Step-1 Draw BC=6.2cm Step-2 Draw an angle PBC=60°

Step-1 Draw BC=6.2cm Step-2 Draw an angle PBC=60°Step-3 Draw an angle QCB=45°

Step-1 Draw BC=6.2cm Step-2 Draw an angle PBC=60°Step-3 Draw an angle QCB=45°Step-4 Take radius 5cm at point B

Step-1 Draw BC=6.2cm Step-2 Draw an angle PBC=60°Step-3 Draw an angle QCB=45°Step-4 Take radius 5cm at point B BA=5cm and it intersecting BP at point A

Step-5 Draw an angle at A , angle RAB=135°

Step-6 AR and CQ intersecting at point D

Hence, ABCD is a required quadrilateral