construct a quadrilateral ABCD, where AB=5cm, BC = 6cm, CD =6.5cm , angle B= 105° and angle C = 75°
Answers
Solution:
Given : A quadrilateral A B CD, in which, AB=5 cm, BC = 6 cm, CD =6.5 cm , angle B= 105° and angle C = 75°
Steps of construction
(1) Draw a line segment B C of length 6 cm.
(2) At Point B and C , with the help of Compass draw angle of 105° and 75° respectively.Name the rays as C M and B Z respectively.
105°→Draw an angle of 120° and 90° and draw angle bisector between 90° and 120°.
75°→Draw angle bisector of 60° and 90°.
(3) From C , mark an arc at a distance of 6.5 cm on ray CM.You will get point D.
(4) From B , mark an arc at a distance of 5 cm on ray B Z.You will get point A.
(5) Join A and D.
This is required trpzoid A B CD.
here, AB ║CD→→∠B+∠C=180°[If sum of interior angles on the same side of transversal is supplementary then lines are parallel.]
Step-by-step explanation:
constructing angle B and angle C
Finding Point A and Point D
joining AD
Labelling quadrilateral ABCD
