Question

construct a quadrilateral ABCD with AB=5.6Cm,BC=4Cm<A=50°,<B=80°,and
<C=125°​

Answer 1

Answer:∠A + ∠B + ∠C + ∠D = 360°

so 50° + 105° + ∠C + 80° = 360°

∠C = 125°

Now we will construct the quadrilateral ABCD

- First we will draw a line AB = 5.6 cm

- Now we will draw ∠BAX = 50° and ∠ABY = 105° (you can use protector for this)

- The radius we will take is 4cm and the center will be B for that you will draw and arc which will intersect the line BY at "C"

- Now we will draw an angle of 125° at "C" and the angle ray line AX at "D"

Step-by-step explanation: