Construct a quadrilateral ABCD with AB = 6 cm, BC = 4 cm, CD = 4 cm, angle ABC = angleBCD = 90°. What kind of quadrilateral is this?
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Answered by
1
Answer:
Step-by-step explanation:
Draw BC = 4 cm . Step II: Construct ∠ABC = 95° at B . Step III : With B as the centre and radius 6 cm, cut off BA = 6 cm
Answered by
0
Answer:
Draw a line sagment BC=4m
Construct angle=ABC=95degree
With B as the centre and radius 6cm,cut off BA=6cm
Construct angle=BCD=90 degree
With as the centre and radius 4cm,cut off CD=4cm
Join=AD
Thus, the required quadrilateral ABCD is obtained.
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