Math, asked by javedmithawala26, 6 days ago

Construct a quadrilateral ABCD with AB = 6 cm, BC = 4 cm, CD = 4 cm, angle ABC = angleBCD = 90°. What kind of quadrilateral is this?​

Answers

Answered by shubhamkh9560
1

Answer:

Step-by-step explanation:

Draw BC = 4 cm . Step II: Construct ∠ABC = 95° at B . Step III : With B as the centre and radius 6 cm, cut off BA = 6 cm

Answered by suhanigupta475
0

Answer:

Draw a line sagment BC=4m

Construct angle=ABC=95degree

With B as the centre and radius 6cm,cut off BA=6cm

Construct angle=BCD=90 degree

With as the centre and radius 4cm,cut off CD=4cm

Join=AD

Thus, the required quadrilateral ABCD is obtained.

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