Question

construct a quadrilateral ABCD ,with AB = 6cm , BC = 4.6 ,CD = AD =5.4 cm and AC = 7 cm​

Answer 1

Answer::

Steps :

1. Draw BC = 5 cm.

2. Draw ∠PCB = 60° and cut CD = 4.5 cm.

3. From B and D, draw arcs of radii 6 cm and 5 cm respectively which intersect at A.

4. Join AB and AD.Thus ABCD is the required quadrilateral.

Answer 2

Answer:

Step 1:- Draw a line segment AB=6cm.

Step 2:- With B as a center and radius BC=4cm, draw an arc.

Step 3:- With A as a center and radius AC=8cm, draw an arc intersecting the previous arc at point C.

Step 4:- Again take B as a center and radius BD=7cm, draw an arc.

Step 5:- With C as a center and radius CD=7cm, draw an arc intersecting the previous arc at point $$D$4.

Step 6:- Join AC,BC,BD,CDandAD.

Thus, ABCD is a required quadrilateral.

$thanks$