Question

construct a quadrilateral EFGH in which EF- 5.3 cm FG-6.3 cm GH-4 cm HF-7.1 cm and EG - 6.4 cm​

Answer 1

Answer:

Steps of construction:-

(a) Draw TE=6cm and bisect it into two equal parts.

(b) Draw up and down perpendiculars to TE.

(c) Draw two arcs of 4.5cm taking E and T as centres, which intersect at S.

(d) Again draw two arcs of 4.5cm taking E and T as centres, which intersects at B.

(e) Join TS,ES,BT and EB.

It is the required rhombus BEST.

Measurement of BE=6.7cm.