construct a quadrilateral in which AB= 4.3cm A=60° BC=3.5cm,CD=2.8cm,AD=3.3cm
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Construction of a quadrilateral ABCD using a ruler and a compass.
Given AB = 4.3 cm. ∠A = 60°. BC = 3.5 cm. CD = 2.8 cm. AD = 3.3 cm.
1. Draw a horizontal line and mark on it AB using (a scale/ruler) of length 4.3cm.
2. At "A" draw a line AE making an angle ∠EAB = 60°. This can be drawn using an instrument directly or by using standard procedure for construction of 60°.
3. Using the compass mark a radius of 3.3 cm and with A as the center, cut the line AE by cutting it with an arc. The intersection is the point D.
4. From D draw a circular arc of radius 2.8 cm. From B draw a circle arc of radius 3.5 cm, to cut the earlier arc. The intersection point is called C.
5. Join BC and CD. We have the quadrilateral ready.
Given AB = 4.3 cm. ∠A = 60°. BC = 3.5 cm. CD = 2.8 cm. AD = 3.3 cm.
1. Draw a horizontal line and mark on it AB using (a scale/ruler) of length 4.3cm.
2. At "A" draw a line AE making an angle ∠EAB = 60°. This can be drawn using an instrument directly or by using standard procedure for construction of 60°.
3. Using the compass mark a radius of 3.3 cm and with A as the center, cut the line AE by cutting it with an arc. The intersection is the point D.
4. From D draw a circular arc of radius 2.8 cm. From B draw a circle arc of radius 3.5 cm, to cut the earlier arc. The intersection point is called C.
5. Join BC and CD. We have the quadrilateral ready.
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