Question

construct a quadrilateral pqrs in which PQ = 5.6 CM, qr = 4.5 cm <p = 70° <Q =110° and <s = 105​

Answer 1

Answer:

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Answer 2

Answer:

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.

Step-by-step explanation:

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