Construct a quadrilateral PQRS in which PQ= 6.5cm, QR=6cm, CD = 4.8cm, ∠P = ∠R =
1000
and ∠S =750
Answers
Answer:
75°
Step-by-step explanation:
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Step-by-step explanation:
Given: In a quadrilateral PQRS, PQ=6.5 cm, QR=6cm, CD=4.8cm and ∠P=∠R=100° and ∠S=75°
To Find: ∠Q and construct a quadrilateral PQRS
Calculation of the angle Q of the quadrilateral PQRS
- Sum of all the angles in a quadrilateral is 360°
- By this statement we can find out the angle Q
In a quadrilateral,
∠P + ∠Q + ∠R + ∠S = 360°
from the given, we know all the angles except ∠Q.
therefore,
100° + ∠Q + 100° + 75° = 360°
By adding all the angle on LHS we'll get,
275° + ∠Q = 360°
now taking 275° to RHS
∠Q = 360° - 275°
∠Q = 85°
So we get ∠Q = 85°
Construction of the Quadrilateral PQRS
STEP 1: Draw the segment PQ of length 5cm
STEP 2: Draw angle PQC measuring 85°
STEP 3: With Q as a center draw an arc of radius 6.5cm such that it cuts the side QC
STEP 4: Draw angle QRF measuring 100°
STEP 5: Draw angle QPG measuring 100°
STEP 6: the point where PG and RF intersect is S
Hence, PQRS is the required quadrilateral.