Question

Construct a quadrilateral PQRS in which PQ= 6 cm, QR = 5 cm, PS = 4.8 cm P= 60" and Q = 75"​

Answer 1

Answer:

P + Q + R + S = 360 ( sum of all internal angles of quadrilateral = 360 )

75 + 105 + 90 + S = 360

270 + S = 360

S = 360-270

= 90

Now after finding all angles quadrilateral PQRS can be drawn by :

1 ) Draw a line segment PQ = 5cm

2) From angle Q draw an angle of 105

and QR of length 6cm

3) At the end of the line QR by taking R as centre draw an angle of 90

4) Now from P as centre draw an angle of 75

5) at last at the point where the line P and Q will meet draw the angle S Of 90

And quadrilateral PQRS is formed.

Answer 2

Answer:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90

⋅

and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60

⋅

and at R, a ray making an angle 120

⋅

which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.