Math, asked by nilushueb, 6 months ago

construct a quadrilateral PQRS such that PQ=6.3cm,PS=3.8cm,Q=95degree , R=85degree , S=110degree​

Answers

Answered by kalivyasapalepu99
1

In Euclidean plane geometry, a quadrilateral is a polygon with four edges (sides) and four vertices (corners). Other names for quadrilateral include quadrangle (in analogy to triangle), tetragon (in analogy to pentagon, 5-sided polygon, and hexagon, 6-sided polygon), and 4-gon (in analogy to k-gons for arbitrary values of k). A quadrilateral with vertices {\displaystyle A}A, {\displaystyle B}B, {\displaystyle C}C and {\displaystyle D}D is sometimes denoted as {\displaystyle \square ABCD}{\displaystyle \square ABCD}.[1][2]

The word "quadrilateral" is derived from the Latin words quadri, a variant of four, and latus, meaning "side".

Quadrilaterals are either simple (not self-intersecting), or complex (self-intersecting, or crossed). Simple quadrilaterals are either convex or concave.

The interior angles of a simple (and planar) quadrilateral ABCD add up to 360 degrees of arc, that is[2]

{\displaystyle \angle A+\angle B+\angle C+\angle D=360^{\circ }.}\angle A+\angle B+\angle C+\angle D=360^{\circ }.

This is a special case of the n-gon interior angle sum formula: (n − 2) × 180°.

All non-self-crossing quadrilaterals tile the plane, by repeated rotation around the midpoints of their edges.

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