Math, asked by premsharma280606, 2 months ago

Construct a quadrilateral PQRS where PQ=3.5 cm QR=6.5 cm angle P= angle R = 105° and angle S= 75°​

Answers

Answered by manasasimhadri2005
8

Answer:

Step-by-step explanation:

The given details are PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°. We know that ∠P + ∠Q + ∠R + ∠S = 360° ∴ ∠Q = 75° Steps to construct a quadrilateral: Step 1- Draw a line PQ = 3.5cm Step 2- Construct and angle of 105° at P. Step 3- Construct and angle of 75° at Q. Step 4- Cut an arc of radius 6.5cm with Q as the center to mark that point as R. Step 5- Construct and angle of 105° at R such that it meets the line segment PX, mark that point as S. Step 6- Now join QR, RS and PS

Answered by xxyogeshxx7
125

Answer:

The given details are PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°.

We know that ∠P + ∠Q + ∠R + ∠S = 360°

∴ ∠Q = 75°

Steps to construct a quadrilateral:

Step 1 - Draw a line PQ = 3.5cm.

Step 2 - Construct and angle of 105° at P.

Step 3 - Construct and angle of 75° at Q.

Step 4 - Cut an arc of radius 6.5cm with Q as the center to mark that point as R.

Step 5 - Construct and angle of 105° at R such that it meets the line segment PX, mark that point as S.

Step 6 - Now join QR, RS and PS.

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