Construct a quadrilateral PQRS where PQ=3.5cm, QR=6.5cm, angle P=75°, angle Q= 105°, angle R=90°.
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The given details are PQ = 3.5 cm, QR = 6.5 cm, ∠P = ∠R = 105° and ∠S = 75°. We know that ∠P + ∠Q + ∠R + ∠S = 360° ∴ ∠Q = 75° Steps to construct a quadrilateral: Step 1- Draw a line PQ = 3.5cm Step 2- Construct and angle of 105° at P. Step 3- Construct and angle of 75° at Q. Step 4- Cut an arc of radius 6.5cm with Q as the center to mark that point as R. Step 5- Construct and angle of 105° at R such that it meets the line segment PX, mark that point as S. Step 6- Now join QR, RS and PSRead more on Sarthaks.com - https://www.sarthaks.com/674009/construct-a-quadrilateralpqrswherepq-3-5-cm-qr-6-5-cm-p-r-105-ands-75
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upper answer is right OK
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